why is this operation equal to 1?

Question

#include<stdio.h>
#include<stdlib.h>

int main(){
float x;
x=4/(4-1);
printf("%f\n", x);

}

when I try to run that on c it makes x equal to 1, i don´t understand why

`x=4/(4-1);` The right side is computed as an integer. --> `x=4./(4-1);` — BLUEPIXY, Mar 01 '17 at 23:36
thx a lot, now if i want to change the 4 for a variable, for example having x=i/(i-1)? — Edu Galindo, Mar 01 '17 at 23:40
thanks, sorry i am really new at programming, why does it not work like i had typed it? — Edu Galindo, Mar 01 '17 at 23:42
The result of an integer operation is computed as an integer rather than a floating point number. In order to compute with a floating point number, you need to mix floating point numbers or type cast (like `(float)`). — BLUEPIXY, Mar 01 '17 at 23:45
or `x = i/(i-1.0f)` or `x= 1.0f*i/(i-1)` or `x= 1.0*i/(i-1)`, or ... — chux - Reinstate Monica, Mar 02 '17 at 00:09

score 1 · Answer 1 · answered Mar 01 '17 at 23:38

1

Because you are making a division between two int, so you'll obtain an int as result.

answered Mar 01 '17 at 23:38

Zeb

ohh so if i want to get a float as a result i have to type "(float)" and place it before the division right? – Edu Galindo Mar 01 '17 at 23:45
Not exactly, you need that each number is a float, for example in this way x=4.0/(4.0-1.0); – Zeb Mar 02 '17 at 23:41

1 Answers1