4
t1<-as.POSIXct("2017-03-02 11:58:20")
t2<-as.POSIXct("2017-03-02 12:00:05")
print(lubridate::as.duration(lubridate::interval(t1,t2)))

[1] "105s (~1.75 minutes)"

Is it possible to have the duration expressed in HH:MM:SS? So in this case it would be:

00:01:45

Sotos
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Alessandro Jacopson
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2 Answers2

4

You can use seconds_to_period from lubridate with sprintf

library(lubridate)
td <- seconds_to_period(difftime(t2, t1, units = "secs"))
sprintf('%02d:%02d:%02d', td@hour, minute(td), second(td))
#[1] "00:01:45"

This is based on an earlier discussion - Converting seconds to days: hours:minutes:seconds in r?

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Karthik Arumugham
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3

To stay in the lubridate mindset:

t1<-as.POSIXct("2017-03-02 11:58:20")
t2<-as.POSIXct("2017-03-02 12:00:05")
dur <- lubridate::as.period(lubridate::as.duration(lubridate::interval(t1,t2)))
sprintf('%02d %02d:%02d:%02d', day(dur), hour(dur), minute(dur), second(dur))

Normally, the period class might be inaccurate (leap days etc) but since it was first passed through duration, it should be right.

takje
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