i have a sql query shown below
CREATE TABLE IF NOT EXISTS `breakup` (
`id` int(7) NOT NULL AUTO_INCREMENT,
`ORDEST` varchar(20) DEFAULT NULL,
`ORDEL` varchar(10) DEFAULT NULL,
`ORPATT` varchar(15) DEFAULT NULL,
`ORITEM` varchar(15) NOT NULL,
`ORZPC` int(7) NOT NULL,
`ORPKG` int(7) NOT NULL,
PRIMARY KEY (`id`),
KEY `ORDEST` (`ORDEST`),
KEY `ORITEM` (`ORITEM`),
KEY `ORPATT` (`ORPATT`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AVG_ROW_LENGTH=96 AUTO_INCREMENT=9 ;
--
-- Dumping data for table `breakup`
--
INSERT INTO `breakup` (`id`, `ORDEST`, `ORDEL`, `ORPATT`, `ORITEM`, `ORZPC`, `ORPKG`) VALUES
(1, 'COLOMBO', '20170402', '000M305', '95815', 2000, 2000),
(2, 'MM', '20170405', 'Z0505', '50968BA', 100, 100),
(3, 'MM', '20170407', 'Z3481', '91123', 1, 1),
(4, 'MM', '20170407', 'Z3481', '91127', 1, 1),
(5, 'MM', '20170407', 'Z3481', '91128', 1, 1),
(6, 'MM', '20170407', 'Z3481', '91987S', 6, 1),
(7, 'MM', '20170407', 'Z3481', '91189C', 6, 1),
(8, 'COLOMBO', '20170415', 'Z0505', '55506', 972, 972);
then i need to genarate php report like this by usung above data; i have tried several times and ended with an error.
Thank you
php code for table heading printing ;
<?php
$sql_e=mysql_query(
"SELECT * FROM breakup
GROUP By ORDEL, ORDEST
ORDER BY ORDEL, ORDEST"
)
or die ("err 120");
while ($row_e = mysql_fetch_array($sql_e)) {
$dest=$row_e['ORDEST'];
$ordel=$row_e['ORDEL'];
echo '<td align="center" bgcolor="#CCCCCC" width="150"><b> '.$ordel."<br>". $dest.' </b></td>';
}
?>
". $dest.' '; } ?> – Tharindu ucsc Mar 08 '17 at 05:54