If Variable doesn't exist echo

Question

I want to write some thing if for example $var doesn't exist this what i want

$var = "Powered by company name";
if(!$var){
echo "doesn't exist ";
}

I want to use it in copyright if my copyright doesn't exist in the page i want to show the msg "doesn't exist "

Possible duplicate of [Check if Variable exists and === true](http://stackoverflow.com/questions/7908163/check-if-variable-exists-and-true) — Masivuye Cokile, Mar 08 '17 at 12:21
You are trying to make sure some copyright notice is in the script? You do know that this is not robust at all? If someone removes the copyright from the script, then why shouldn't the check also get removed? — arkascha, Mar 08 '17 at 12:22
Can you give us a more practical example of what you want to achieve? What you provided is really vague. — apokryfos, Mar 08 '17 at 12:26

score 0 · Answer 1 · answered Mar 08 '17 at 12:20

0

you can not do that insted you do define $var firstlike demo

$var="";

now code

if($var==""){
}else{
}

answered Mar 08 '17 at 12:20

This will raise an exception if variable is not defined. – Mr. Alien Mar 08 '17 at 12:21
yes that why i say for define $var="";on page start – Nishit Manjarawala Mar 08 '17 at 12:22
But he is not sure if the variable is defined, if he is defining, then he does not need to check for it's existence. – Mr. Alien Mar 08 '17 at 12:23

score -1 · Answer 2 · answered Mar 08 '17 at 12:19

-1

if (isset($var) && ($var === true)) { ... }

answered Mar 08 '17 at 12:19

Bilal Ahmed

2 Answers2