if (cond1 and cond2) or (not cond1 and not cond2):
Is there a simpler way to write this in Python?
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2You mean `if (cond1 = cond2)`? – Ken White Mar 09 '17 at 03:54
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1@KenWhite: that'd by a syntax error. ;-) – Martijn Pieters Mar 09 '17 at 03:56
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You want the inverse of `xor`, (so `xand`?), which is `bool(cond1) == bool(cond2)`. See the duplicate (with `!=` inverted to `==`). You can drop the `bool()` calls if both `cond1` and `cond2` are themselves boolean results. – Martijn Pieters Mar 09 '17 at 03:58
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@MartijnPieters: OK. The logic is correct; the question still asks about equality of both variables (both true or both false). Fill in the correct syntax for the language, whether that's `=`, `==`, `equals`, or something else. :-) – Ken White Mar 09 '17 at 04:00
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@SamuelLiew: yes, which is nothing more than the inversion of XOR. So `bool(a) != bool(b)` (XOR) becomes `bool(a) == bool(b)`. I do cover that in my comment. – Martijn Pieters Mar 09 '17 at 04:09
