Combine two regex patterns: case insensitivity and escape backslash

Question

I know that I can use case insensitive approach as follows:

var name = "test A/c";
{name: new RegExp('^'+name+'$', "i")}

Now I want to escape backslash in above expression. I know how to escape backslash:

/\//ig;

But I dont know how to use these two patterns in combination with each other.

I'm confused. Where is the backslash in the first expression that you want to escape? — KernelPanic, Mar 09 '17 at 06:22
`A/c` has a forward slash not backward slash and it doesn't require escaping while using `RegExp` object — anubhava, Mar 09 '17 at 06:34
@anubhava Please take a look at this question for more details: http://stackoverflow.com/questions/42680530/escape-forward-slash — Vishal, Mar 09 '17 at 06:35
@anubhava At last found the mistake. new RegExp() function does not need to escape backslash. My mistake was, I was sending this value from url and thus it was counted as new parameter after slash. Thank you for helping. — Vishal, Mar 09 '17 at 07:58

m87 · Answer 1 · 2017-03-09T06:39:43.743

1

You could do it using the following way ...

var name = "test A/c".replace(/(?=\/)/g, '\\\\');
{name: new RegExp('^'+name+'$', "ig")}

edited Mar 09 '17 at 06:39

answered Mar 09 '17 at 06:28

m87

I have given the example here. But in reality, the value of variable name will be coming from database. – Vishal Mar 09 '17 at 06:29
You should explain why the double slashes are necessary. `Teach a man to fish`... – Regular Jo Mar 09 '17 at 06:29
still getting the same result. Please take a look at this post for more details: http://stackoverflow.com/questions/42680530/escape-forward-slash – Vishal Mar 09 '17 at 06:43
1

At last found the mistake. new RegExp() function does not need to escape backslash. My mistake was, I was sending this value from url and thus it was counted as new parameter after slash. Thank you for helping. – Vishal Mar 09 '17 at 07:57

Kamuran Sönecek · Accepted Answer · 2017-03-09T07:09:13.080

1

You can use replace in second expression.

var name = "test A/c"; {name: new RegExp('^'+name.replace(/\//g,'\\/')+'$', "i")}

edited Mar 09 '17 at 07:09

answered Mar 09 '17 at 06:33

Kamuran Sönecek

No, still getting the same results after trying to replace as you said. – Vishal Mar 09 '17 at 06:40
Please take a look at this post: http://stackoverflow.com/questions/42680530/escape-forward-slash – Vishal Mar 09 '17 at 06:43
I am on mobile. I will check it in an hour. – Kamuran Sönecek Mar 09 '17 at 07:01
That also doesn't make any difference. – Vishal Mar 09 '17 at 07:21
1

At last found the mistake. new RegExp() function does not need to escape backslash. My mistake was, I was sending this value from url and thus it was counted as new parameter after slash. Thank you for helping. – Vishal Mar 09 '17 at 07:57

score 1 · Answer 3 · edited May 23 '17 at 10:30

1

Take a look at this post Escaping Strings in JavaScript and check if this is what you are looking for.

quoting from above link:

function addslashes( str ) { return (str + '').replace(/[\\"']/g, '\\$&').replace(/\u0000/g, '\\0'); }

edited May 23 '17 at 10:30

Community

answered Mar 09 '17 at 06:36

Praveen Devarao

Good job on citing relevant information, though thi is more of a comment. You should copy relevant text here. If that url is changed, the link becomes useless. – Regular Jo Mar 09 '17 at 06:43
At last found the mistake. new RegExp() function does not need to escape backslash. My mistake was, I was sending this value from url and thus it was counted as new parameter after slash. Thank you for helping. – Vishal Mar 09 '17 at 07:58

3 Answers3