Python - Conflict with Regex and Exclusive or Operator

Question

I'm importing regex for a word count in a string, and I'm trying to use the ^ operator. Although, the compiler is recognizing the ^ as part of regex, and not the exclusive or operator. This is my code:

import re as regex

count = len(regex.findall(r'\w+', question))


if count < 3:

    magicball.say("No Spam Allowed!!")

elif "will" in question ^ "can" in question ^ "did" in question ^ "is" in question ^ "do" in question ^ "are" in question ^ "has" in question ^ "does" in question ^ "is" in question:

    verified = True
    print(oringinalquestion)

The line that I'm getting the error is where it says elif. Basically, is there a way to tell the compiler that I want to use the exclusive or operator? Thanks in advance!

I do not see any conflict in your example. Regex has nothing to do with your error. — DYZ, Mar 12 '17 at 06:48

score 1 · Answer 1 · answered Mar 12 '17 at 06:36

1

If you can add the error trace it would be great. My suspicion is that that you need to put brackets on every boolean statement like this:

elif ("will" in question) ^ ("can" in question) ^ ("did" in question) ^ ("is" in question) ^ ("do" in question) ^ ("are" in question) ^ ("has" in question) ^ ("does" in question) ^ ("is" in question):

answered Mar 12 '17 at 06:36

Den1al

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It didn't work. The error is `unclosed string on line 10. Did you forget a quote?` – Nathan Chan Mar 12 '17 at 17:23
That would be because of a typo on your part. – Karl Knechtel Oct 16 '22 at 02:42

score 0 · Answer 2 · answered Mar 12 '17 at 06:46

Operator ^ has higher precedence than operator in. Your expression is equivalent to "will" in (question ^ "can") in (question ^ "did") ..., while what you presumably want it ("will" in question) ^ ("can" in question) ^ ("did" .... So, use parentheses to disambiguate your expression.

Python - Conflict with Regex and Exclusive or Operator

2 Answers2