Python 3 - How to continuously remove letters from a sentence?

Question

alphabet_dic = ['a','b','c','d','e','f','g','h','i','j','k','l','n','o','p','q','r','s','t','u','v','w','y','z','m']

doc = Document('test3.docx')
firstSen = doc.paragraphs[0].text
print (firstSen)

indexLetters = 0
while indexLetters < len(c_dic):
    d_dic = c_dic[indexLetters]
    indexLetters += 1
    secondSen = firstSen.replace(d_dic,"")    
    print (secondSen)

The test document holds the sentence "Hello There". I am attempting to make a loop in where it checks the dictionary for a long range of specific letters and slowly loops and remove the letters from "Hello There".

Idea:

Sentence = Hello There

helloDic = ['h','e','l','o']

Desire Result = Tr

Any suggestions or better way to do this?

score 2 · Answer 1 · edited May 23 '17 at 11:53

2

Applying str.replace several times comes to mind at first, but it is really a non-performant method to do that (Python str.translate VS str.replace)

As a nice alternative, you could modify your "dictionary" to create a real dictionary, compatible with str.translate (adding the uppercase letters too). Then you only have to apply the str.translate function to your string using the new dict:

Sentence = "Hello There"

helloDic = ['h','e','l','o']

rep_dic = {ord(k):None for k in helloDic + [x.upper() for x in helloDic]}

print(Sentence.translate(rep_dic))

result:

Tr

(spaces were preserved)

edited May 23 '17 at 11:53

Community

1
1

answered Mar 12 '17 at 20:17

Jean-François Fabre

137,073
23
153
219

Can't you use the `deletechars` argument provided in the `translate` method? `S.translate(table [,deletechars]) -> string` – elena Mar 12 '17 at 20:25
`deletechars` is python 2 only. In python 3, you have to map your chars to `None`. Question is tagged "python 3" – Jean-François Fabre Mar 12 '17 at 20:27

Elmex80s · Answer 2 · 2017-03-12T21:53:20.733

0

The straightforward solution

sentence = 'Hello There'

hello_dic = ['h','e','l','o']

r = [s for s in sentence if s.lower() not in hello_dic]

print ''.join(r)

Output

' Tr'

edited Mar 12 '17 at 21:53

answered Mar 12 '17 at 21:07

Elmex80s

3,428
1
15
23

1

could be simplified by `s for s in sentence if s.lower() not in hello_dic` since `hello_dic` only contains lowercase letters. – Jean-François Fabre Mar 12 '17 at 21:20
and my turn to advise you to use `set` instead of `list`. For 4 letters it's no big a deal, though. – Jean-François Fabre Mar 12 '17 at 21:22

Python 3 - How to continuously remove letters from a sentence?

2 Answers2