How to grep a directory for a string, rewrite it to something else and save in bash?

Question

I have a bash script that does the following:

Removes a CSS directory
Copies over new SASS from source
Runs gulp task to generate CSS again

After I copy the SASS over, I would like to do the following before generating CSS again:

Find any occurrence of ('/assets and change it to ('/themes/custom/mytheme/assets in any of the files in the SASS directory.

How can I do that?

What have you tried so far ? Some simple `awk` / `sed` could easily do that — Aserre, Mar 13 '17 at 16:00
Better replace the text in the SASS source with a variable and let SASS do the substitution... — clt60, Mar 13 '17 at 17:10

score 0 · Answer 1 · answered Mar 13 '17 at 18:17

As was already mentioned, this can be done for example with a basic sed substitution. The only thing to look out for, is to escape the slashes and to use -i to edit files in place.

sed -i "s/('\/assets/('\/themes\/custom\/mytheme\/assets/" /path/to/SASS/*

How to grep a directory for a string, rewrite it to something else and save in bash?

1 Answers1