Array in c, char type

Question

#include <stdio.h>
int main ()
{
char c[10];
int k=0;
printf("please enter the element value in character\n");
for(k=0;k<10;k++)
{     
scanf("%c",&c[k]);
}
for(k=0;k<10;k++)
{
printf("Value in char is %c\n",c[k]);
}
return 0;
}

//problem is that i can only initialize value of 5 char not 10. My IDE is code::blocks with GNU GCC COMPILER .

@pm100 the loop stops after 5 inputs instead of 10 as stated. — Weather Vane, Mar 13 '17 at 18:19
To add to what @WeatherVane said: some of the characters you obtained are `\n` (the ENTERs). — pmg, Mar 13 '17 at 18:22
@Maddy *what* "does not work". I amended your program and it accepts and then prints 10 inputs. — Weather Vane, Mar 13 '17 at 18:22
it is spiking every other scanf or in other words scanf is being called twice everytime idk why — Maddy, Mar 13 '17 at 18:23
Try inputting all in a row: `"elevendigitENTER"` or `"9876543210ENTER"`. — pmg, Mar 13 '17 at 18:25
do you mean the loop stops inputting or it stops outputting? — pm100, Mar 13 '17 at 18:30

score 0 · Accepted Answer · answered Mar 13 '17 at 18:23

0

You can use scanf("%c%*c"); to read the newline after your character. The %*c matches a single character, but the asterisk indicates that the character will not be stored anywhere. This has the effect of consuming the newline character generated by the enter key so that the next time you call scanf() you are starting with an empty input buffer.

answered Mar 13 '17 at 18:23

cleblanc

3,678
1
13
16

thanks,but can u explain ? – Maddy Mar 13 '17 at 18:27
Each `scanf("%c")` call reads just on character and leaves the newline character stuck in the stdin buffer. You need to consume that character before calling `scanf(...)` a second time or it will return the newline character '\n', – cleblanc Mar 13 '17 at 18:30

philezwini · Answer 2 · 2017-03-13T19:06:25.477

0

When you press enter from your keyboard, the program reads the char you have just entered (e.g 'a') along with a new-line character("\n") from pressing the enter button. You must handle this in your code by writing your scanf the following way: scanf(" %c" , &c[k]) . There must be a whitespace before the %c. This tells the compiler to ignore all whitespace characters.

edited Mar 13 '17 at 19:06

answered Mar 13 '17 at 18:56

philezwini

1
3

Array in c, char type

2 Answers2