How do I make a methods that splits a String into individual letters of type String?

Question

In the following snippet:

static Scanner userInput = new Scanner(System.in);
static String str;

public static void main(String[] args) {

    str = userInput.nextLine();

}

 public String wordSplitter() {     
    char b;     

    for(int i = 0; i < numbers.length(); i += 1) 
    b = str.charAt(i);
    return b;       
}

the statement "return b;" gives me an error because my method should return a String, but b is a char.

So how do I somehow make b into a String? Or is there a better way to split Strings into letters of type String?

thanks

Lots of way to do this. http://stackoverflow.com/questions/8172420/how-to-convert-a-char-to-a-string — SedJ601, Mar 14 '17 at 06:00
Is b being overwritten on purpose? Also, is wordSplitter instance method on purpose? — dev8080, Mar 14 '17 at 06:01
What exactly are you trying to do? What is the purpose of `wordSplitter` method? — Pshemo, Mar 14 '17 at 06:27

score 1 · Answer 1 · answered Mar 14 '17 at 08:23

How about this?

public String splitStringIntoLetters(){
        String toBeSplit = "abcdefg";
        char [] toBeSplitChar = toBeSplit.toCharArray();
        return java.util.Arrays.toString(toBeSplitChar);
}

this returns something like: [a, b, c, d, e, f, g]

Once you get the string just perform the operation that you want on the string. e.g.

String testStr = splitStringIntoLetters();
System.out.println(testStr.replace("["," ").replace("]"," ").split(","));

ΦXocę 웃 Пepeúpa ツ · Answer 2 · 2017-03-14T06:05:27.723

0

There are many ways to achieve that, you can use/return Character.toString(b) or String.valueOf(b) static methods.

here and here the Doc

public String wordSplitter() {     
    char b;     
    ....// do something and assign b
    return Character.toString(b);       
}

edited Mar 14 '17 at 06:05

answered Mar 14 '17 at 05:58

ΦXocę 웃 Пepeúpa ツ

47,427
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score 0 · Answer 3 · answered Mar 14 '17 at 06:01

public String wordSplitter() {     
    char b;     

    for(int i = 0; i < numbers.length(); i += 1) 
    b = String.valueOf(str.charAt(i));
    return b;       
}

You can try above code.

   String string = Character.toString(ch);
   String string = String.valueOf(ch);

This both above method can convert your character to String. Hope this will helps you.

score 0 · Answer 4 · edited Mar 14 '17 at 06:40

0

You can try it like these，first of all I think it should be i<str.legth; and you can handle it like this, return b+"";

edited Mar 14 '17 at 06:40

Pshemo

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answered Mar 14 '17 at 06:13

jean wong

1
1

..?? forgot something?? – ΦXocę 웃 Пepeúpa ツ Mar 14 '17 at 06:32
Char plus " " is a string,it is convenient than other methods. – jean wong Mar 15 '17 at 09:47

score 0 · Answer 5 · answered Oct 13 '18 at 21:16

Seems your code is mainly designed to eat CPU performance.

Normally you would replace :

for(int i = 0; i < numbers.length(); i += 1) 
    b = str.charAt(i); 
return b;

By

return str.charAt(numbers.length()-1);

And if you insist on returning a String you would do

 return String.valueOf(str.charAt(numbers.length()-1));

... but I struggle understanding what the purpose of this could be

How do I make a methods that splits a String into individual letters of type String?

5 Answers5