How do I get the rows to columns to be the row and vice versa

Question

Here is some code I wrote

def binomial_coefficient(x,y):

    if y == x:
        div = 1
    elif y == 1:         
        div = x
    elif y > x:          
        div = 0
    else:                
        a = math.factorial(x)
        b = math.factorial(y)
        c = math.factorial(x-y)  
        div = a // (b * c)
    return(div)

def problem_9():
    for k in range(6):
        empty = '\t'
        for zed in range(1,6):
            X_sub = (10*zed,(1/5)*zed)
            n = X_sub[0]
            P = X_sub[1]
            formula = binomial_coefficient(n,k)*(P**k)*(1-P)**(n-k)
            empty = empty + str(formula) + '\t'
        print(empty)

problem_9()

I have the code giving me the correct mathematical values but I need the first column to switch places with the first row. I would like the same thing to happen for each subsequent iteration of the loops. Can anyone help?

You mean the *transpose*? – Willem Van Onsem Mar 14 '17 at 17:16 — Willem Van Onsem, Mar 14 '17 at 17:16
Yes, Transpose is the proper word. – Trea704 Mar 14 '17 at 17:20 — Trea704, Mar 14 '17 at 17:20

score 0 · Answer 1 · answered Mar 14 '17 at 17:19

0

just permute the indices :

for zed in range(1,6):
    empty = '\t'
    for k in range(6):

answered Mar 14 '17 at 17:19

B. M.

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Thank you! that worked fine. – Trea704 Mar 14 '17 at 17:47

How do I get the rows to columns to be the row and vice versa

Here is some code I wrote

1 Answers1