Using the "super" keyword in a class method decleration

Question

Why is "this super" not allowed in a Java class method definition? For example,

class Dog{
  public <T super Dog> void display(ArrayList<T> t){
     t.add()
  }
}

[that might be wort a read](http://stackoverflow.com/a/4343547/1799530) — SomeJavaGuy, Mar 16 '17 at 10:49
Possible duplicate of [Difference between super T> and extends T> in Java](http://stackoverflow.com/questions/4343202/difference-between-super-t-and-extends-t-in-java) — S.L. Barth is on codidact.com, Mar 16 '17 at 10:50

score 0 · Accepted Answer · answered Mar 17 '17 at 14:19

Because super of a class is always Object class so it means it act as
public &ltObject&gt void display(ArrayList <Object> t)
{}

And it allow every class object to pass in display function parameter which is not good for genrics.So that's why super is not allow in function definition there.

Using the "super" keyword in a class method decleration

1 Answers1