Linux equivalent of including the classpath during compilation

Question

I'm following a guide that only includes compilation instructions on windows. How would one run this build.bat file on Linux?

The batch file looks like this:

@echo off
@echo Compiling...
javac -classpath ..\..\lib\OneWireAPI.jar;%classpath% -d . .\src\*.java

And when I run the javac command on Linux, it fails:

javac -classpath ../../lib/OneWireAPI.jar;%classpath% -d . ./src/ReadTemp.java

The output is:

javac: no source files

What is the correct way to do this?

Possible duplicate of [Classpath does not work under linux](http://stackoverflow.com/questions/4528438/classpath-does-not-work-under-linux) — OldProgrammer, Mar 16 '17 at 18:59

score 1 · Accepted Answer · answered Mar 16 '17 at 18:55

1

On Linux, you have to use : (colon) in place of ; (semicolon) as the path separator in Java options.

Also, if you have a classpath variable, in most common Linux shells it is referenced by $classpath rather than by %classpath%

javac -classpath ../../lib/OneWireAPI.jar:$classpath -d . ./src/ReadTemp.java

answered Mar 16 '17 at 18:55

rrobby86

Beat me by 7 seconds :) – Mad Physicist Mar 16 '17 at 18:56
Also, probably need to capitalize CLASSPATH – Mad Physicist Mar 16 '17 at 18:57
It depends: environment variables are usually uppercase, but can also be lowercase. It just matters to use the same case in declaration and use. – rrobby86 Mar 16 '17 at 18:59

score 1 · Answer 2 · answered Mar 16 '17 at 18:55

You have two items that did not get translated correctly from Windows CMD to Unix:

Path separator ; should be :.
Environment variables should be changed from %classpath% to $CLASSPATH format. Note that pretty much everything is case-sensitive in Linux, including environment variable names, and the Java path is traditionally all-caps.

Try

javac -classpath ../../lib/OneWireAPI.jar:$CLASSPATH -d . ./src/ReadTemp.java

2 Answers2