How to write a program that prompts the user to enter a number n, then prints all even squares between 1 and n

Question

This is what i have so far:

n=int(input("Enter a number"))

for i in range (1,n+1,):

  if(i%2==0):

    print(i)

So for example, if the user enters 100, the program should print the following:

Read: [Formatting code in posts](http://stackoverflow.com/help/formatting) — Barmar, Mar 16 '17 at 20:41
Could you post the traceback? The indentation was wrong but that could have been you pasting it in wrong. — TankorSmash, Mar 16 '17 at 20:41
Instead of testing whether a number is a square, just generate all the squares. And you don't need to test if a number is even, because even squares are always the square of even numbers. So just increment by 2 instead of 1. — Barmar, Mar 16 '17 at 20:46

shad0w_wa1k3r · Answer 1 · 2017-03-16T20:48:07.143

0

The ** operator in python acts as a power operator. So, x-squared is basically x**2, and x**0.5 is square root of x.

n = int(input("Enter a number"))

for i in range(2, n**0.5+1, 2):
    print(i**2)

edited Mar 16 '17 at 20:48

answered Mar 16 '17 at 20:42

shad0w_wa1k3r

1

Use `range(2, n**0.5+1, 2)` so you step by 2 instead of 1. Then you don't need to test if `sqr` is even. – Barmar Mar 16 '17 at 20:47
Easy miss, thanks for that. – shad0w_wa1k3r Mar 16 '17 at 20:48

1 Answers1