Ajax from Python, without using libraries - how do I do it?
How would I update something at http://localhost/update.php?text=Hello world?
This question is helpful, but what about the Ajax parameters to the URL?
Asked
Active
Viewed 40 times
-1
Community
- 1
- 1
Mawg says reinstate Monica
- 38,334
- 103
- 306
- 551
-
Possible duplicate of [Creating a raw HTTP request with sockets](http://stackoverflow.com/questions/5755507/creating-a-raw-http-request-with-sockets) – Mar 16 '17 at 22:37
-
But what about the Ajax part? The parameters to the URL? – Mawg says reinstate Monica Mar 16 '17 at 22:55
-
As usual, the cowardly downvote gvies no reason. – Mawg says reinstate Monica Mar 17 '17 at 08:28
1 Answers
0
From @unwind's answer to this question:
use urllib.
From the examples in the documentation:
>>> import urllib >>> params = urllib.urlencode({'spam': 1, 'eggs': 2, 'bacon': 0}) >>> f = urllib.urlopen("http://www.musi-cal.com/cgi-bin/query?%s" % params) >>> print f.geturl() # Prints the final URL with parameters. >>> print f.read() # Prints the contents
Community
- 1
- 1
Mawg says reinstate Monica
- 38,334
- 103
- 306
- 551