Replace ' character by " using regex expression

Question

I get a string: "{ a: '123', b: '234'}", I want to make it to be "{ "a": "123", "b": "234" }" by using regex expression. Could anyone explain/guide me how do I do this? The following is my trial.

str.replace(/[']/,'"').replace(/(['"])?([a-z0-9A-Z_\-]+)(['"])?\s*:/g, '"$2":')

did you miss a colon after "b" or you want this to be parsed? — binariedMe, Mar 17 '17 at 10:04
Yes, I actually want this to be parsed. Thank you for your remind, I will edit my question — Tel lui, Mar 17 '17 at 10:05
*"...using regex expression."* Why? Would other options work if available? — T.J. Crowder, Mar 17 '17 at 10:06
And where are you getting this string from? Is the source trusted? — T.J. Crowder, Mar 17 '17 at 10:11
@Aron: Again: The input is invalid JSON. The `a` and `b` would have to be in `"`, and the values would have to be in `"`, not `'`. — T.J. Crowder, Mar 17 '17 at 10:18
@T.J.Crowder Thank you. However, I am not clear, do you mean that the ' cannot be replaced to be " using the regular expression and JSON parse together, as I just want to get the json as { "a": "123", "b": "234"} only. — Tel lui, Mar 17 '17 at 10:21
@Tellui: I understand your end goal. I'm asking you where the string comes from and whether you can trust that source. — T.J. Crowder, Mar 17 '17 at 10:24
@T.J.Crowder I think I find my problem now. You are right, in fact I think I am getting strings from the html template using the angular directive. However, it failed in this case. Thanks a lot. — Tel lui, Mar 17 '17 at 10:31
Possible duplicate of [convert invalid JSON string to JSON](http://stackoverflow.com/questions/24462658/convert-invalid-json-string-to-json) — Ali Hesari, Mar 20 '17 at 14:01

score 2 · Answer 1 · answered Mar 17 '17 at 10:04

2

Just use JSON.parse. That's what it's made for.

answered Mar 17 '17 at 10:04

Aron

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But `"{ a: '123', b: '234'}"` is no valid JSON – Andreas Mar 17 '17 at 10:05
I actually want the JSON to BE {"a":, "123", "b": "234"}. I don't understand why the topic is down voted. – Tel lui Mar 17 '17 at 10:12
@Tellui you've just put a comma after the `a:`. Is that intentional? Because of your (maybe) typos it's difficult to understand what you're after: a parser for faulty JSON or just a regular JSON parser? – Aron Mar 17 '17 at 10:14
Okay. Let me make these all more clear :) by editing. – Tel lui Mar 17 '17 at 10:15

Ali Hesari · Accepted Answer · 2017-03-20T08:20:55.097

1

Try this code:

var yourjson = "{ a: '123', b: '234'}";
var jsontemp = yourjson.replace((/([\w]+)(:)/g), "\"$1\"$2");
var correctjson = jsontemp.replace((/'/g), "\"");
alert(correctjson);

jsfiddle

edited Mar 20 '17 at 08:20

answered Mar 20 '17 at 08:03

Ali Hesari

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Replace ' character by " using regex expression

2 Answers2