Powershell Echo Statement + Variable In One line

Question

I'm running a script, and I want it to print a "statement + variable + statement" at the end [when successful]. I've tried a few thing but it always returns as 3 separate lines, instead of one. The Echo "" before and after is just to make it easier to read when printed by spacing it out, I've tried it with and without and I get the same result.

$filename = "foo.csv"

    echo ""
    echo "The file" $filename "has been processed."
    echo ""

I get this:

The file
foo.csv
has been processed.

Possible duplicate of [How to concatenate strings and variables in PowerShell?](http://stackoverflow.com/questions/15113413/how-to-concatenate-strings-and-variables-in-powershell) — BioGenX, Mar 17 '17 at 15:52

score 39 · Accepted Answer · answered Mar 17 '17 at 16:03

39

If you use double quotes you can reference the variable directly in the string as they allow variable expansion, while single quotes do not allow this.

$filename = "foo.csv"
Write-Output "The file $filename has been processed."

-> The file foo.csv has been processed.

Also, echo is actually just an alias for Write-Output, so I've used the full name.

answered Mar 17 '17 at 16:03

henrycarteruk

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So simple. I got thrown off because it gets grayed out. I thought it was being converted to plain text. Thanks. – physlexic Mar 17 '17 at 16:11
1

I'd certainly recommend reading up on [double vs single quotes](http://jon.netdork.net/2015/09/08/powershell-and-single-vs-double-quotes/), such a small thing can have a very big effect :) – henrycarteruk Mar 17 '17 at 16:18
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this not work properly with $args[0] if they are few - its print it all args :/ – Gorodeckij Dimitrij Dec 10 '17 at 17:19
2

@GorodeckijDimitrij yes, arrays and strings need to be handled differently. – henrycarteruk Dec 11 '17 at 09:40

score 10 · Answer 2 · edited Dec 03 '19 at 11:09

10

echo ("The file "+ $filename +" has been processed.")

edited Dec 03 '19 at 11:09

4b0

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answered Dec 03 '19 at 11:07

tom

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Please add a description to ur answer – Ankit Kante Dec 03 '19 at 11:27

score 7 · Answer 3 · answered Mar 17 '17 at 15:55

7

In powershell, you can use Write-Host as follows:

$filename = "foo.csv"
Write-Host 'The file' $filename 'has been processed.'

-> The file foo.csv has been processed.

answered Mar 17 '17 at 15:55

BioGenX

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When writing out an `object` then `Write-Host` will give you the object's type, not its contents. Better to use`Write-Output` – Dr Rob Lang Jul 10 '18 at 15:18

Powershell Echo Statement + Variable In One line

3 Answers3