Using a variable as a path BAT

Asked Mar 17 '17 at 22:11

Active Mar 18 '17 at 00:57

Viewed 53 times

I have a program that searchs for a file on the local disk, then copy it in its' own directory.

SET MyProgramDir=%~dp0
for /f "delims=" %%i in ('where /r c:\ *MyFile') do set MyPath=%%i
set MyFilePath=%MyPath:~0,-6%
xcopy "%MyFilePath%" "%MyProgramDir%"

But it says that the path is invalid; 0 file copied. I don't get it, I tried with and without ", I tried to do like

set MyPath=%MyFilePath:~3%
set BatPath=%MyProgramDir:~3%
xcopy "C:\%MyPath" "C:\BatPath"

edited Mar 18 '17 at 00:57

asked Mar 17 '17 at 22:11

Maximilien

1

Other than `xcopy "C:\%MyPath" "C:\BatPath"` should be `xcopy "C:\%MyPath%" "C:\%BatPath%"` your routine works quite happily for me. What values are in `myprogramdir` and `myfilepath`? – Magoo Mar 17 '17 at 22:33
Maybe it's because the directory contains characters like ÌÚÑ¶ÓÎÏ ..? – Maximilien Mar 18 '17 at 00:21
Here's the program anyway: http://pastebin.com/EFJCf6et – Maximilien Mar 18 '17 at 00:29
what does the directory contain? – phuclv Mar 18 '17 at 01:58
More than likely the non-ASCII names. Try using the short names instead (dir /x ... will show the short name) – Magoo Mar 18 '17 at 03:52
It is possible that you are not removing enough characters and you are ending in [this problem](http://stackoverflow.com/q/25840861/2861476) – MC ND Mar 18 '17 at 07:51
Removing a backslash \ at the end fixed it. Thanks ! – Maximilien Mar 18 '17 at 14:41

Using a variable as a path BAT

0 Answers0