$a=(float) 640.81;
$b=(float) 636.85;
$c=(float) 3.96;
$d= $a-$b-$c;
echo $d;
Why am getting -7.7271522513911E-14 this value? It should be 0 right.
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jewelhuq
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That is basically 0. Chalk it up to rounding error. – Carcigenicate Mar 18 '17 at 18:19
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1[Floating point precision](https://en.wikipedia.org/wiki/Floating-point_arithmetic#Accuracy_problems) – Mark Baker Mar 18 '17 at 18:28