Getting list of years between two years?

Question

I have this method :

public function getYears($startYear = 1990, $endYear = date ('Y')){
    $years = [];
    $date = new \DateTime();

    $years[$date->format('Y')] = $date->format('Y'); 
    while ($endYear <= $startYear){
       $date->add(new \DateInterval('P1Y'));
       $years[$date->format('Y')] = $date->format('Y');
       $endYear++;
    }
   return $years;
}

This piece of code doens't work, but you get the idea what I want ? How can i make this work ? thx

Possible duplicate of [How to calculate the difference between two dates using PHP?](http://stackoverflow.com/questions/676824/how-to-calculate-the-difference-between-two-dates-using-php) — Fky, Mar 20 '17 at 15:25
@Fky The post that you suggested is using the `strtotime` method. I want to use the methods from `DateTime()` class . Thx — Attila Naghi, Mar 20 '17 at 15:26
Why not just use PHP's [range](http://php.net/range) function? — mrun, Mar 20 '17 at 15:29
@Chester ALWAYS read a little bit more than just the accepted answer! — Pieter van den Ham, Mar 20 '17 at 15:50

score 4 · Accepted Answer · edited Mar 20 '17 at 15:34

4

If I understand your question, this is really easy:

$arYears = range(1990, date('Y'));

edited Mar 20 '17 at 15:34

AbraCadaver

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answered Mar 20 '17 at 15:28

Mihai

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1

Thx a lot, I need coffee :P – Attila Naghi Mar 20 '17 at 15:30
and if you really want keys `$arYears = array_combine($arYears, $arYears);` – AbraCadaver Mar 20 '17 at 15:34

JM-AGMS · Answer 2 · 2018-09-11T17:00:44.400

1

If you want to stick with a loop, you can do it this way:

function getYears($startYear = 1990, $endYear = date ('Y')) {
  $years = [];
  for ($y = $startYear; $y < $endYear; $y++) {
    $years[] = $y;
  }
  return $years;
}

edited Sep 11 '18 at 17:00

answered Mar 20 '17 at 15:29

JM-AGMS

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Getting list of years between two years?

2 Answers2