Java is Pass-By-Value and Pass-By-Reference Both

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Is Java pass by reference?

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possible duplicate of [Is Java pass by reference?](http://stackoverflow.com/questions/40480/is-java-pass-by-reference) and many of these: http://stackoverflow.com/search?q=java+pass+by+value — Adam Paynter, Nov 27 '10 at 10:29
If you want a fast answer, why not search for it? http://www.google.co.uk/search?q=java+pass+by+value 23,400,000 hits! — Peter Lawrey, Nov 27 '10 at 11:25

score 1 · Answer 1 · answered Nov 27 '10 at 10:32

1

Java doesn't pass method arguments by reference - it passes them by value.

answered Nov 27 '10 at 10:32

Jon Black

1

+1, with the comment that *references* are passed *by value*. – Adam Paynter Nov 27 '10 at 10:35

score 0 · Answer 2 · answered Nov 27 '10 at 10:32

0

Have a look at this:

answered Nov 27 '10 at 10:32

Ristovak

score -5 · Answer 3 · answered Nov 27 '10 at 10:30

-5

The Java compiler decides what's best.

answered Nov 27 '10 at 10:30

Eamorr

What do you mean by that? The Java compiler emits *Java bytecode* and *Java bytecode* has rules governing this. I don't think the compiler has a choice in the matter. – Adam Paynter Nov 27 '10 at 10:32

3 Answers3