xpath select all attributes ending with foo?

Question

Is it possible with XPATH/XSLT 1.0 to select all attributes ending with "Foo"?

I'm writing some XSLT to get the list of all values of all attributes for all "InterestingElement"s where the attribute name ends with "Foo".

Actually I also want to filter out those where the value is empty ""

I tried specifying a stylesheet for XSLT 2.0 but got xsl:version: only 1.0 features are supported:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
            xmlns:fo="http://www.w3.org/1999/XSL/Format"
            xmlns:xs="http://www.w3.org/2001/XMLSchema"
            xmlns:fn="http://www.w3.org/2005/xpath-functions"
            xmlns:xdt="http://www.w3.org/2005/xpath-datatypes">

So far I have:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes"/>
<xsl:template match="/">
<xsl:for-each select="//InterestingElement">
<xsl:value-of select="__what goes here?__"/><xsl:text>
</xsl:text>
</xsl:for-each>
<xsl:text>end</xsl:text>
</xsl:template>
</xsl:stylesheet>

And here's some sample XML:

<?xml version="1.0"?>
<root>
  <Other Name="Bob"/>
  <InterestingElements>
    <InterestingElement AttrFoo="want this"
                        Attr2Foo="this too"
                        Blah="not this"
                        NotThisFoo=""/>
  </InterestingElements>
</root>

can you also share `xml` sample, desired output and code you've already tried? — Andersson, Mar 20 '17 at 19:50

score 4 · Answer 1 · answered Mar 20 '17 at 19:50

4

XPath 2.0 Solution

XPath 2.0 alone can solve this; in XSLT 2.0, no xsl:for-each is needed -- just xsl:value-of.

This XPath,

string-join(//InterestingElement/@*[ends-with(name(.), 'Foo') and . != ''], ' ')

will return a space-separated list of the (non-empty) values of all InterestingElement attributes whose name ends with Foo.

answered Mar 20 '17 at 19:50

kjhughes

106,133
27
181
240

2

or you could also eliminate the `string-join()` and use the `@separator`: `` – Mads Hansen Mar 21 '17 at 02:41
@MadsHansen: Good idea. – kjhughes Mar 21 '17 at 02:43

score 3 · Accepted Answer · edited Mar 21 '17 at 22:10

3

XPath 1.0 Solution

string-join and ends-with are XPath 2.0. For 1.0, you can use the following, which returns all the values separated by space:

<xsl:for-each select="//InterestingElement/@*['Foo' = substring(name(.), string-length(name(.)) - string-length('Foo') +1) and . != '']">
  <xsl:value-of select="." /><xsl:text> </xsl:text>
</xsl:for-each>

To get the matching attribute names instead of values, change the select to select="name(.)"

Based on kjhughes answer and this SO answer.

edited Mar 21 '17 at 22:10

user1011471

1,090
2
14
34

answered Mar 20 '17 at 20:01

AntonH

6,359
2
30
40

@user3735178 I forgot that string-join is XSLT 2.0 ... I edited my answer to put it in a `` instead. – AntonH Mar 20 '17 at 20:27
Possibly ` ` or ` `, but I'm not 100% sure of that. – AntonH Mar 20 '17 at 20:58

xpath select all attributes ending with foo?

2 Answers2

XPath 2.0 Solution

XPath 1.0 Solution