I have a table looked like this
mysql> select * from rc;
+----+----------------------------+----------------------------+----------------------------+
| id | business_date | cutoff_dt | recon_dt |
+----+----------------------------+----------------------------+----------------------------+
| 1 | 2017-03-21 16:50:29.032000 | 2017-03-21 16:50:31.441000 | 2017-03-21 16:50:32.832000 |
+----+----------------------------+----------------------------+----------------------------+
1 row in set (0.00 sec)
I want to run query
-Select * from rc
where business_date = '2017-03-17'
- if
cutoff_dt` is null or empty, it will display null, otherwise display not null
I wrote it into shell script.
#! /bin/bash
mysql -u root -p <<rcard
use rcard;
SELECT *
(CASE WHEN (cut_off_dt = "NULL")
THEN
echo "Null"
ELSE
echo "NOT NULL"
END)
from rc WHERE business_date = '2017-03-17';
rcard
But I get error
ERROR 1064 (42000) at line 2: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(CASE WHEN (cut_off_dt = "NULL")
THEN
echo "Null"
ELSE
' at line 2
Is it the correct way to write the IF ELSE in MySQL ?