Why doesn't my Java code run?

Question

class Name{

    String name;
    Name(String name){
        this.name = name;
    }
    void changeName(String name){
        this.name = name;

    }
    String getName(){
        return this.name;
    }

    void swap(Name other_Name_object){

        String temp;
        temp = other_Name_object.getName();
        other_Name_object.changeName(this.name);
        this.name = temp;

    }

    public String toString(){
        return this.name;
    }
}

I'm not sure why my code doesn't run on my java compiler. It has the same name as the file names.java

do you have a main method ? like `public static void main(String[] args){}` — 97hilfel, Mar 22 '17 at 09:21
I just needed to add public static void main(String args[]) to the class. Thanks — Jorge Corral, Mar 22 '17 at 09:37

Steve Smith · Answer 1 · 2017-03-22T09:25:36.710

3

For any Java code to run, it needs a main method to tell the JVM where to start.

You would need to add this:

public static void main(String args[]) {
    new Name();
}

to your class.

edited Mar 22 '17 at 09:25

answered Mar 22 '17 at 09:21

Steve Smith

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score 0 · Answer 2 · answered Mar 22 '17 at 09:39

Use the following code and see your output. You need to have a main method in order to tell the JVM where to look for a start.

class HelloWorld {

  public static void main(String[] args) {
    Name n1 = new Name("John Doe");
    System.out.println(n1.getName());
  }

}

class Name {
  String name;
  Name(String name) {
    this.name = name;
  }
  void changeName(String name) {
    this.name = name;

  }
  String getName() {
    return this.name;
  }

  void swap(Name other_Name_object) {

    String temp;
    temp = other_Name_object.getName();
    other_Name_object.changeName(this.name);
    this.name = temp;

  }

  public String toString() {
    return this.name;
  }
}

Why doesn't my Java code run?

2 Answers2