Why are there multiple ways of initializing variables in c++?

Question

Why are there multiple ways of initializing variables in c++ instead of just one? From my knowledge you can do these:

int x = 0;
int y (2);
int c {3};

Thanks!

Past mistakes + backwards compatibility = redundancy. This is very opinion based and broad. — nwp, Mar 22 '17 at 15:03
@nwp, nah sure? I mean the answer should probably just be something like: "it is simply for readability" or "this one ... is quite different because it takes blablabl" :) — , Mar 22 '17 at 15:04

score -2 · Answer 1 · answered Mar 22 '17 at 15:03

-2

Oh, it is because , all of datatypes are an object. They all have blind initializers, that is same as the default-constructor(initializer) of the classes.

answered Mar 22 '17 at 15:03

G.Andrei

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Why are there multiple ways of initializing variables in c++?

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