When I want to split the String "aaaa|bbbbb|123456" with the method String.split("|"), the result is unexpected .
My code:
String s = "aaaa|bbbbb|123456";
String[] temp = s.split("|");
for (String str:temp) {
System.out.println(str);
}
But the result is:
a
a
a
a
|
b
b
b
b
b
|
1
2
3
4
5
6
are there anything special with char "|" ?
In Java the following characters has to be escaped in regular expressions
.[]{}()*+-?^$|
You could either escape the | character during split like
string.split("\\|");
You could also achieve the same using StringTokenizer as follows
String test = "abc.def.123";
StringTokenizer token = new StringTokenizer(test, "|");
while (token.hasMoreTokens()) {
System.out.println(token.nextToken());
}
To know more about the list of characters that has to be escaped with regex pattern look at this post.
You need to escape the pipe:
String[] temp = s.split("\\|");
The pipe symbol | has a special meaning in regex, used to indicate an alternation. Your original code resulted in splits happening between every character, which isn't what you want.
Use escape sequences,
String s="aaaa|bbbbb|123456";
String [] temp=s.split("\\|");
for(String str:temp) {
System.out.println(str);
}
The Sting split(String regex) method wants a regular expression as its parameter.It splits this string around matches of the given regular expression.
A preceding backslash ("\") turns a metachacter into a literal character. Because this is also the Java escape character in strings, you need to use "\" to present the backslash character. To split a string with a literal '|' character in Java,
you must use split("\\|")
. For example,
String s="aaaa|bbbbb|123456";
String [] temp=s.split("\\|");
for(String str:temp) {
System.out.println(str);
}
