How to generate Random point(x,y) in Java

Question

I want to generate a random point(x,y) in java which should lie within a 2D plane {(1,1)(1,-1)(-1,1)(-1,-1)} where both positive & negative X & Y axis is considered.Thank you

You create two random floating point values between 0 and 1; and then you randomly multiply with -1. All of that is really basic stuff that you can look up within minutes using your favorite search engine — GhostCat, Mar 23 '17 at 10:10
Also, please specify what you mean by "random". Which probability mass function should be used? — Turing85, Mar 23 '17 at 10:16

score 2 · Accepted Answer · answered Mar 23 '17 at 10:16

Take a look at article https://www.tutorialspoint.com/java/util/java_util_random.htm. All you need to do is to generate pairs of floats in range (-1,1). You should use method nextFloat() from class Random. It will give you numbers in range (0,1). Then multiply it by 2 and subtract 1 and you will have numbers in desired interval.

score 0 · Answer 2 · edited May 23 '17 at 12:00

0

Please use SecureRandom see: StackOverflow

edited May 23 '17 at 12:00

Community

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answered Mar 23 '17 at 10:28

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Jjingo · Answer 3 · 2017-03-23T11:33:44.483

Use this method below to return you the random points

public String randXYPoint(){
    //For x and y, the maximum point is 1 and Minimum point is -1
    //maximum number
    int min = -1;
    //minimum number
    int max = 1;

    // generates x values
    double xValue = min + Math.random() * (max - min);
    // generates y values
    double yValue = min + Math.random() * (max - min);
    //returns and converts points to string 
    return  String.valueOf(xValue)+ ", "+ String.valueOf(yValue);
}

Just call the method

System.out.println(randrandXYPoint())

How to generate Random point(x,y) in Java

3 Answers3