following up the creation of a chart from another question I had raised, and by studying this thread that contains information on how to bisect a nested array, I enriched my chart to zoom-able and resposnive.
I am so close to completing it, just a few things missing that I thought would be a lot easier. I am currently stuck at the tooltips. The desired effect is for a tooltip to appear when hovering over the chart and show current date, line names and line values. I tried a lot of things, but can't get the expected result.
Moreover, I am not sure about the bisection. Am I doing it right? The original dataset is turned to a nested array and then for bisection it is manipulated again. Is this the right way to do it or would it be safe to use the original dataset?
I am looking for fail-safe to create tooltips that would work in other cases as well - not just this specific chart, so any advice and/or suggestions are more than welcome.
My code for the tooltip is as follows:
var mousemoveFunc = function(d, i) {
var d, d0, d1, i, x0, left, mouse, top;
x0 = xz.invert(d3.mouse(this)[0]);
ds = dataGroup.map(function(e) {
var i = bisectDate(e.values, x0, 1),
d0 = e.values[i - 1],
d1 = e.values[i];
return d = x0 - d0.date > d1.date - x0 ? d1 : d0;
});
mouse = d3.mouse(svg.node()).map(function(d) {
return parseInt(d);
});
left = Math.min(containerwidth, mouse[0]+margin.left+margin.right);
top = Math.min(containerheight, mouse[1]+margin.top+margin.right);
tooltip.data(ds).classed('hidden', false).attr('style', 'left:' + left + 'px;top:' + top + 'px;margin-top:' + (-margin.top) + 'px;').html(function(d,i) {
for (var i = 0; i < ds.length; i++){
if (ds[i].date === d.date){
return ds[i].name + ' ' + ds[i].value;
}
}
});
};
..I am almost certain that it is wrong to reattach data(ds) on the tooltip, but it was the only way I could manage to show results.
I have created the following fiddle: https://jsfiddle.net/2en21Lqh/4/
:/ Now that I am currently writing the post, I just realised that attaching data on a single element is totally wrong, since the function(d) would only run once.