Print the following pattern in shortest no of characters

Question

What can be the smallest possible code in any language(I guess Python will win) to print "001002003004005006007008009010011012013014015016017018019020021022023024025"

Basically it is counting from 1 to 25.

Welcome to SO. This is not a tutorial/learning site. There is Google, for that — Rocketq, Mar 24 '17 at 07:22

score 2 · Answer 1 · answered Mar 24 '17 at 06:58

2

Try this

print("".join(map(lambda x:str(x).zfill(3),range(1,26))))

or

print(reduce(lambda x,y:x+str(y).zfill(3),range(1,26),""))

answered Mar 24 '17 at 06:58

ignite234

21
3

Can we do better using regex? – Anonymous Man Mar 24 '17 at 07:06

score 0 · Answer 2 · edited May 23 '17 at 12:00

0

You could use one of these methods to pad the numbers with zero's after converting them to strings. Then simply join the strings together and print or print each string. But the first one should get the job done.

for i in range(1,26):
    print(str(n).zfill(3), end="")

edited May 23 '17 at 12:00

Community

1
1

answered Mar 24 '17 at 06:54

avlec

396
1
15

Can we do better using regex? – Anonymous Man Mar 24 '17 at 07:06
I don't believe there'd be a "nice" way of doing it in regex. – avlec Mar 24 '17 at 07:14

score 0 · Answer 3 · answered Jun 14 '17 at 07:03

0

Try this in python3

    [print("%03d"%i,end='') for i in range(1,26)]

answered Jun 14 '17 at 07:03

Ankit

130
3
13

Print the following pattern in shortest no of characters

3 Answers3