Parse error: syntax error, unexpected end of file in php. Couldn't find where did i do wrong?

Question

I got an error

Parse error: syntax error, unexpected end of file in C:\xampp\htdocs\Web_app\nav.php on line 26

With this code

    <nav class="navbar navbar">`
    <div class="container-fluid">
    <div class="navbar-header">
    <a class="navbar-brand" href="#"></a>
    </div>
    <ul class="nav navbar-nav navbar-right">

    $_SESSION['client_id'] ='1';
>if client is not logged in
    //client login
    <?php 
    if(!isset($_SESSION['client_id']))
    { 
     ?>
    <li><a href="#"> Login</a></li>
    <?php} 

       else{?>
    <li><a href="#"> Edit Account </a></li>
    <li><a href="#"> My Account </a></li>
    <li><a href="#"> log out</a></li>
    <?php}?>
    </ul>
    </div>
    </nav>

I have configured the php.ini file but still can't solve the problem. Is there any syntax related problem?

This is your actual code? `$_SESSION['client_id'] ='1';` is not in PHP... — chris85, Mar 25 '17 at 05:48
I would suggest getting a php aware code editor/ide, it will help suss out the syntax errors in this code. — Orangepill, Mar 25 '17 at 05:49

Gohel Dhaval · Answer 1 · 2017-03-25T06:36:23.063

0

You can write $_SESSION['client_id'] ='1'; this inside php tag not and add white space in

edited Mar 25 '17 at 06:36

answered Mar 25 '17 at 05:46

Gohel Dhaval

820
1
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The current code doesn't seem like it'd throw a parser error. Can you elaborate? – chris85 Mar 25 '17 at 05:52

score 0 · Answer 2 · answered Mar 25 '17 at 05:55

0

You need whitespace after <?php for it to be recognized properly. So change

<?php}

to

<?php }

Also, the assignment

$_SESSION['client_id'] = '1';

needs to be inside <?php ... ?>, not in the HTML section.

answered Mar 25 '17 at 05:55

Barmar

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Solved it. Thank You very much for the assist – Towfiq Omi Mar 25 '17 at 06:00

Parse error: syntax error, unexpected end of file in php. Couldn't find where did i do wrong?

2 Answers2