Long.toBinaryString not returning expected binary string for 827.0

Question

I'm working with doubles and need to find the binary version of 827.0.

From looking around the way to do it is this.

So I do:

double myDouble = 827.0;
Long.toBinaryString(Double.doubleToRawLongBits(myDouble))

However this is returning:

100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000

instead of 1100111011.

Any idea where I'm going wrong?

Answer 1

this should work:

double myDouble = 827.0;
System.out.println(Long.toBinaryString((long) myDouble));