Counting the appearance of each number in a list and printing them on separate lines

Question

I'm very new to Python and I need to make the code that counts the number of times each number appears in a list associated with a specific key. The program should then print out those counts on separate line

I was able to print out the count, but I have trouble printing them on separate lines. Here is what I was able to do so far:

import json

#####

def read_json(filename):
    dt = {}

    fh = open(filename, "r")
    dt = json.load(fh)

    return dt

##### 

def num_counter(dt):

    numbers = dt["daily_stock_prices"]


    counter = {}

    for number in numbers:
        counter[number] = 0

    for number in numbers:
         counter[number] += 1

    print counter

#####

filename = raw_input('Please enter the file name: ')

#####

r = read_json(filename)
num_counter(r)

I have tried to work on printing the counter on separate lines as seen below, but I remain unsuccessful. Any advice? I'm also not sure where to include it in my code.

def print_per_line(number_counts):

    for number in number_counts.key():

            count = word_counts[word]       

            print word,count

Here is the list if needed:

{
    "ticker": "MSFT",
    "daily_stock_prices": [0,1,5,10,12,15,11,9,9,5,15,20]
}

The final output should be:

item: count
item: count
...

What about showing us example of the file content and example output? — Nf4r, Mar 27 '17 at 18:39
Try using [pprint](https://docs.python.org/3/library/pprint.html#pprint.pprint) — wwii, Mar 27 '17 at 18:43

chinmay · Answer 1 · 2017-03-27T18:52:07.927

1

Try this:

def num_counter(dt):
    numbers = dt["daily_stock_prices"]
    counter = {}
    for number in numbers:
        counter[number]= counter.get(number, 0) + 1
    return counter

def print_per_line(num_count):
    for k,v in counter.iteritems():
       print str(k) + ":  " + str(v)

# You call them like this
r = read_json(filename)
num_count = num_counter(r)
print_per_line(num_count)

edited Mar 27 '17 at 18:52

answered Mar 27 '17 at 18:44

chinmay

672
6
15

is it possible to continue the code from what I started please – J. Doe Mar 27 '17 at 18:48
@J.Doe updated the answer, is that what you looking for ? – chinmay Mar 27 '17 at 18:52
I'm not allowed to add a function call. Sorry forgot to mention – J. Doe Mar 27 '17 at 19:15

Thane Plummer · Answer 2 · 2017-03-27T19:17:25.413

0

Here is how to do it both with and without the collections module.

import collections
import json

# Here is the sample data
data = """{
    "ticker": "MSFT",
    "daily_stock_prices": [0,1,5,10,12,15,11,9,9,5,15,20]
}"""

# It's easiest to parses it with as JSON.
d = json.loads(data)

# You can use the collections module to count.
counts = collections.Counter(d['daily_stock_prices'])

# Or you can create a dictionary of the prices.
pricedict = {}
for price in d['daily_stock_prices']:
    if pricedict.has_key(price):
        pricedict[price] += 1
    else:
        pricedict[price] = 1

# Print output - you could substitute counts for pricedict. 
for k,v in pricedict.iteritems():
    print("{} - {}".format(k, v))

OUTPUT

edited Mar 27 '17 at 19:17

answered Mar 27 '17 at 18:56

Thane Plummer

7,966
3
26
30

Is there a way without using collections. I haven't learned that command yet – J. Doe Mar 27 '17 at 19:01
@J.Doe Have given the answer without that below – chinmay Mar 27 '17 at 19:03
Yes there is -- I'll post an update. The collections module just makes it easier. Just saw that chinmay showed how to do that. I'll post something different so you can get a handle on Python's dictionary container. – Thane Plummer Mar 27 '17 at 19:04
Chinmay added another function call when I'm not suppose to – J. Doe Mar 27 '17 at 19:16
Just to make sure pricedict is your counter – J. Doe Mar 27 '17 at 19:29

Counting the appearance of each number in a list and printing them on separate lines

2 Answers2