Select only such items that contain any element in int array

Question

Assume I have a class:

public class Item
{
    ...
    public IEnumerable<int> ClientsIds { get; set; }
}

And the following code:

List<Item> items = GetItems();
int[] ids = GetIds();

Now I need to select only such items that contain any element in ids int array. How can I do it?

You can use LINQ. Did you try any of their methods? – krillgar Mar 28 '17 at 13:07 — krillgar, Mar 28 '17 at 13:07
Please read: http://stackoverflow.com/q/16322/1715004 – Filipe Borges Apr 03 '17 at 15:03 — Filipe Borges, Apr 03 '17 at 15:03
And this: https://stackoverflow.com/help/how-to-ask – Filipe Borges Apr 03 '17 at 15:04 — Filipe Borges, Apr 03 '17 at 15:04

René Vogt · Accepted Answer · 2017-03-28T13:14:39.160

0

Well a simple Where should do it:

var filteredItems = items.Where(item => 
                      item.ClientIds.Any(ids.Contains)).ToList();

I don't see a need for an extension method here, but you could of course encapsulate it:

public static IEnumerable<Item> FilterItems(this IEnumerable<Item> source, IEnumerable<int> filter)
{
    return source.Where(item => item.ClientIds.Any(filter.Contains));
}

edited Mar 28 '17 at 13:14

answered Mar 28 '17 at 13:07

René Vogt

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Select only such items that contain any element in int array

1 Answers1