.js scope program throwing error

Question

I've looked into it and cannot figure out why this program is throwing an error in the console.

var laundryRoom = 'Basement';
var mailRoom = 'Room 1A';

function myApartment() {
  var mailBoxNumber = 'Box 3';
  var laundryRoom = 'In-unit';
  console.log('Mail box: ' + mailBoxNumber + ', Laundry:' + laundryRoom);
}

console.log('Laundry: ' + laundryRoom + ', Mail: ' + mailRoom);
console.log(myApartment());

Output:

Laundry: Basement, Mail: Room 1A
Mail box: Box 3, Laundry:In-unit
undefined

Everything seems fine until this last "undefined".

Any insight would be appreciated.

You are trying to print the result returned by the function, but it doesn't return anything. — PianoSong, Mar 28 '17 at 22:55
**myApartment is a function** The return value of a function is undefined. Please put a return in your function. — Robert I, Mar 28 '17 at 22:55

score 1 · Answer 1 · edited Mar 28 '17 at 22:58

1

myApartment() doesn't return anything explicitly, so it implicitly returns undefined. Just call myApartment() directly, not console.log(myApartment());.

edited Mar 28 '17 at 22:58

Bergi

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answered Mar 28 '17 at 22:55

Ramanlfc

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score 0 · Answer 2 · answered Mar 28 '17 at 22:55

0

myApartment is a function

The return value of a function is undefined.

Please put a return in your function.

answered Mar 28 '17 at 22:55

Robert I

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.js scope program throwing error

2 Answers2