Code:
let fun = x => x * x;
-> undefined
typeof fun.call.call
-> "function"
fun.call.call()
VM251:1 Uncaught TypeError: fun.call.call is not a function
Why is fun.call.call is not a function when typeof fun.call.call -> "function"?
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Saravana
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What is purpose of chained `.call.call`? – guest271314 Mar 29 '17 at 17:04
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1No purpose. Just noticed something weird. – Saravana Mar 29 '17 at 17:04
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Note, no value is passed to `.call()` for `x`, you can use `fun.call(null, 2)` to get expected result – guest271314 Mar 29 '17 at 17:06
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1[Related answer](http://stackoverflow.com/a/40884841/2419531). This is clearer than the one linked as duplicate. – Saravana Mar 29 '17 at 17:14
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Following comment by @Bergi at linked Question/Answer `Function.call.call(fun, null, 2)` should return expected result – guest271314 Mar 29 '17 at 17:23