Python check if element of array contains string

Question

I have an array that has 1 element. This element contains: print(results_read[0])

[(u'n04019541', u'puck', 0.57829314), (u'n02974003', u'car_wheel', 0.24903433), (u'n03483316', u'hand_blower', 0.025689969), (u'n02910353', u'buckle', 0.015434729), (u'n04542943', u'waffle_iron', 0.012205523)]

How can I check if it contains 'car_wheel'? I tried:

if 'car_wheel' in results_read:
      print('yes')
else:
    print('no')

Is there any other way to do this?

duplicate of http://stackoverflow.com/questions/3437059/does-python-have-a-string-contains-substring-method — yar, Mar 30 '17 at 00:17

score 2 · Accepted Answer · answered Mar 30 '17 at 00:17

2

It seems you have a list of list of tuples, you need to loop through the list to do the check one by one; If you just want to know if any tuple contains car_wheel, you can use any for that:

any('car_wheel' in t for t in results_read[0])
# True

answered Mar 30 '17 at 00:17

Psidom

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1

THANK YOU! exactly what I was looking for, will put down as answer in 5min! – Powisss Mar 30 '17 at 00:20

score 1 · Answer 2 · answered Mar 30 '17 at 00:17

You can do something like this :

results_read = [(u'n04019541', u'puck', 0.57829314), (u'n02974003', u'car_wheel', 0.24903433), (u'n03483316', u'hand_blower', 0.025689969), (u'n02910353', u'buckle', 0.015434729), (u'n04542943', u'waffle_iron', 0.012205523)]

if 'car_wheel' in [results[1] for results in results_read] :
      print('yes')
else:
    print('no')

This will result in :

yes

Python check if element of array contains string

2 Answers2