how can I split a string and store it in a temporary variable

Question

I have a data, which is nothing but a string b'365,7,7675962680, 4040.I want to split this data and want to store only 7675962680 to any temporary variable.I don not know, how to split and pick that particular data in python. I have a small code, please help me to solve these issue

manage.py

def data(self, data):
    data1 = data # b'365,7,7675962680, 4040
    # want to split these and store 7675962680 in a variable

Note the question about "convert a string to ip address" - it looks like you're working on the same exercise at the same time. — TigerhawkT3, Mar 31 '17 at 10:31

score 1 · Accepted Answer · answered Mar 31 '17 at 10:21

1

You can use something like this:

def get_data(data):
    data = data.decode()
    data_list = data.split(',')
    return data_list[2]

a = get_data(b'365,7,7675962680, 4040')
print(a)
>> 7675962680

answered Mar 31 '17 at 10:21

Yuval Pruss

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Surajano · Answer 2 · 2017-03-31T10:23:55.520

0

assuming,

s ="365,7,7675962680, 4040"
s.split(',')[2]
'7675962680'

edited Mar 31 '17 at 10:23

answered Mar 31 '17 at 10:21

Surajano

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1

Be careful! `TypeError: a bytes-like object is required, not 'str'` – Yuval Pruss Mar 31 '17 at 10:23

score 0 · Answer 3 · answered Mar 31 '17 at 10:22

0

def data(self, data):
    # data = b'365,7,7675962680, 4040
    # data MUST be converted to str before splitting it
    data1 = data.decode('utf8').split(',')[2]
    print(data1)  # 7675962680
    print(type(data1))  # str

answered Mar 31 '17 at 10:22

nik_m

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how can I split a string and store it in a temporary variable

3 Answers3