I'm using XCode 8.3. if I fire this command in Terminal for making an archive as shown below. It shows this kind of error. Can you help me to find out the solution?
xcodebuild -configuration Release -exportArchive -exportFormat ipa -archivePath "/Users/Desktop/Demo.xcarchive" -exportPath "/Users/Desktop/Demo.ipa" -exportProvisioningProfile "Demo Development"
xcodebuild: error: invalid option '-exportFormat'
Usage: xcodebuild [-project <projectname>] [[-target <targetname>]...|-alltargets] [-configuration <configurationname>] [-arch <architecture>]... [-sdk [<sdkname>|<sdkpath>]] [-showBuildSettings] [<buildsetting>=<value>]... [<buildaction>]...
xcodebuild [-project <projectname>] -scheme <schemeName> [-destination <destinationspecifier>]... [-configuration <configurationname>] [-arch <architecture>]... [-sdk [<sdkname>|<sdkpath>]] [-showBuildSettings] [<buildsetting>=<value>]... [<buildaction>]...
xcodebuild -workspace <workspacename> -scheme <schemeName> [-destination <destinationspecifier>]... [-configuration <configurationname>] [-arch <architecture>]... [-sdk [<sdkname>|<sdkpath>]] [-showBuildSettings] [<buildsetting>=<value>]... [<buildaction>]...
xcodebuild -version [-sdk [<sdkfullpath>|<sdkname>] [<infoitem>] ]
xcodebuild -list [[-project <projectname>]|[-workspace <workspacename>]] [-json]
xcodebuild -showsdks
xcodebuild -exportArchive -archivePath <xcarchivepath> -exportPath <destinationpath> -exportOptionsPlist <plistpath>
xcodebuild -exportLocalizations -localizationPath <path> -project <projectname> [-exportLanguage <targetlanguage>...]
xcodebuild -importLocalizations -localizationPath <path> -project <projectname>