How to access arguments between chained promise

Question

I have the below code:

vm.testService.getUser(id, name)
.then((resultA) => {
    return vm.testService.getUserInfo(id, name);
})
.then(() => {
    // will process resultA from first .then
});

I need to access resultA on the second .then. Thanks in advance.

what's the sense of two `then`s when they depend on each other? — Legends, Mar 31 '17 at 15:10

score 0 · Accepted Answer · answered Mar 31 '17 at 15:10

0

One way is to assign the response of the first then to a variable and access that variable in the second then

check the code snippet

let response

vm.testService.getUser(id, name)
  .then((resultA) => {
    response = resultA
    return vm.testService.getUserInfo(id, name);
  })
  .then(() => {
    console.log(response)
    // will process resultA from first .then
  });

answered Mar 31 '17 at 15:10

Geeky

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I've already thought of assigning it to a higher scope variable. But aside from this, is there any other way? – jengfad Mar 31 '17 at 15:17
Can't answer the question anymore, but you can return an array [resultA, vm.testService.getUserInfo(id, name)] or use Promise.all as well. – Ronan Mar 31 '17 at 15:17
Marking this as an answer since this has less risk on our current implementation. Thanks! – jengfad Apr 11 '17 at 10:22

score 0 · Answer 2 · answered Mar 31 '17 at 15:11

You could store the result of the first callback in the external scope

let result;
vm.testService.getUser(id, name)
.then((resultA) => {
    result = resultA;
    return vm.testService.getUserInfo(id, name);
})
.then(() => {
    // 'result' will now equal resultA
});

How to access arguments between chained promise

2 Answers2