I am a coding-beginner and would like to hear your advice relating to following solution of this exercise:
Write a program that loops prompting for positive or zero integers of data type long. Then the number of digits the integer consists of (in decimal representation) should be printed to stdout. Entering a negative number immediately stops the program. Output examples: 0 has 1 digit. 999 has 3 digits. etc.
I've written the code below and according to the tests I did, the program fulfills all given tasks. But what do you think about it? How can I improve it?
(And I also think that I am not allowed to use any finished helpful function in any c-library. It is just 'plain' C coding or so. Idk how to describe it.)
(The programming language is C)
#include <stdio.h>
int main(void)
{
long number;
int n=0;
do
{
printf("Enter a number: ");
scanf_s("%ld", &number);
if (number > 0)
{
while (number != 0)
{
number /= 10;
n++;
}
}
else if(number == 0){
n = 1;
}
else {
exit();
}
printf("The number you've entered has %d digits.\n\n",n);
n = 0;
} while (getchar() != 'EOF');
return 0;
}