Sorting unique objects on basis of other states

Question

I have collection of employees with states as name,salary,id.

    TreeSet ts=new TreeSet();
    ts.add(new Employee("neeraj", 10000, 123));
    ts.add(new Employee("neeraj", 10000, 789));
    ts.add(new Employee("ankit", 30000, 345));
    ts.add(new Employee("ankit", 40000, 456));

How to sort employees with unique name on basis of salary?

Implement `Comparator` interface and use this implementation along with your collection upon sorting. — , Apr 01 '17 at 19:05
The [duplicate](http://stackoverflow.com/q/4258700/5221149) is old, but does have a Java 8 answer [further down](http://stackoverflow.com/a/36367245/5221149). — Andreas, Apr 01 '17 at 19:08

Alex Romanov · Answer 1 · 2017-04-01T19:19:38.123

0

Java 8 solution:

Collections.sort(employees, Comparator.comparing(Employee::getName)
    .thenComparing(Report::getSalary));

edited Apr 01 '17 at 19:19

answered Apr 01 '17 at 19:08

Alex Romanov

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That will sort *purely* by `salary`. OP wants to *"sort employees **with unique name** on basis of salary"*, i.e. sort *primarily* by `name`, *secondarily* by `salary`. – Andreas Apr 01 '17 at 19:09
how to check unique names? – Neeraj Thakur Apr 01 '17 at 19:12
@Andreas Yea, right you are. Thank's, i've edited my answer. – Alex Romanov Apr 01 '17 at 19:14
can it done by overriding equals method? – Neeraj Thakur Apr 01 '17 at 19:16
@NeerajThakur No, either implement `Comparable` and the `compareTo` method, or provide a `Comparator`, e.g. as shown in this answer for Java 8, or as shown in the [duplicate link](http://stackoverflow.com/q/4258700/5221149). – Andreas Apr 01 '17 at 19:19

Sorting unique objects on basis of other states

1 Answers1