How do I write a regex expression saying 'and NO whitespaces'?

Question

I was wondering how I would write a regex expression which says 'and NO whitespaces'.I need to implement this into the following if statement, see below:

$('#postcode').blur(function(){
    var postcode = $(this), val = postcode.val();

    if((val.length >= 5) && (*******)){ 
       postcode.val(val.slice(0, -3)+' '+val.slice(-3)).css('border','1px solid #a5acb2'); 
    }else{ 
       $(this).css('border','1px solid red'); 
    }
});

Any help is greatly appreciated, Thanks

score 4 · Accepted Answer · answered Dec 01 '10 at 10:22

4

Try this:

&& (!val.match(/\s/))

match return null if there are no spaces (or at least one space), so you can use it as a condition.

answered Dec 01 '10 at 10:22

Kobi

135,331
41
252
292

1

If you really want to, you can combine the length check into the regex using `if(val.match(/^\S{5,}$/))` (note the upper-case S), but I'm not sure it's better. – Kobi Dec 01 '10 at 10:31

score 1 · Answer 2 · answered Dec 01 '10 at 10:23

1

&& (val.indexOf(" ") == -1)

Note: Regex shouldn't be used if other options are readily available.

answered Dec 01 '10 at 10:23

darioo

46,442
10
75
103

True, but `\s` also checks for tabs and newlines. Usually people refer to `" "` as "space" and the rest as "whitespace", but it is a better solution for normal spaces. – Kobi Dec 01 '10 at 10:26
Good point. If this is only a single-line edit control, `space` is the only reasonable whitespace. However, if it's a textarea, there can be tabs, and linebreaks, and whatnot (these can also be pasted into a text input field from clipboard). Regex is actually reasonable here, as it matches any kind of whitespace. – Piskvor left the building Dec 01 '10 at 10:27
@Kobi, @Piskvor: you are both correct. Combination of " ", tabs, newlines with all all their nice `\r`, `\n` variants can make whitespace matching problematic. In that case, regex is the best solution, but my answer is based on OP's question ;-) – darioo Dec 01 '10 at 10:31

score 1 · Answer 3 · edited May 23 '17 at 10:33

1

Would cleaning the whitespaces before line 3 of your code help? (probably less intrusive)

edited May 23 '17 at 10:33

Community

1
1

answered Dec 01 '10 at 10:25

Ryan Fernandes

8,238
7
36
53

score 1 · Answer 4 · answered Dec 01 '10 at 10:31

1

You can do both in the same regexp (guessing postcode is digits).

('1234567').match(/^\d{5,}$/) // ['1234567']
('1234').match(/^\d{5,}$/) // null
('12 34').match(/^\d{5,}$/) //null
('123 4567').match(/^\d{5,}$/) //null

so instead of:

if((val.length >= 5) && (*******)){
    //code
}

use:

if(val.match(/^\d{5,}$/)) {
    //code
}

answered Dec 01 '10 at 10:31

fredrik

17,537
9
51
71

1

I've just posted something similar in a comment. You may want `\S` instead of `\d`, depending on possible values. – Kobi Dec 01 '10 at 10:33

How do I write a regex expression saying 'and NO whitespaces'?

4 Answers4