Generate decreasing list of integers using python range

Question

This is a simple question. I have

range(1, 11)[::-1]

which gives me

[10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

Is there a 'cleaner' way to generate the above list? With a single function perhaps?

What's wrong with `range(10,0,-1)`? (`list(range(10,0,-1))`, if you use Python-3.x) — DYZ, Apr 05 '17 at 20:04
Nothing :) let me try that again, didn't work earlier for some reason — AsheKetchum, Apr 05 '17 at 20:04
I think I was trying to write `range(0, 10, -1)` which did not work. — AsheKetchum, Apr 05 '17 at 20:06
Like the slicing syntax `[start:stop:step]`, the built-in `range(start, stop, step)` works with the same parameters. — Michael H., Apr 05 '17 at 20:06
That makes a lot of sense :) Thank you for the clarification — AsheKetchum, Apr 05 '17 at 20:07
Possible duplicate of [Explain Python's slice notation](http://stackoverflow.com/questions/509211/explain-pythons-slice-notation) — DYZ, Apr 05 '17 at 20:07
@DYZ The question isn't necessarily a duplicate, but the link does answer my question :P — AsheKetchum, Apr 05 '17 at 20:08

score 22 · Accepted Answer · answered Apr 05 '17 at 20:04

22

You can use that range(10, 0, -1)

answered Apr 05 '17 at 20:04

Moi Syme

score 4 · Answer 2 · answered Apr 05 '17 at 20:04

4

Using numpy you could do

import numpy as np
np.arange(10, 0, -1)

answered Apr 05 '17 at 20:04

pingul

Giannis Spiliopoulos · Answer 3 · 2017-04-05T20:05:34.057

1

I don't know if it's cleaner but you could also use:

reversed(range(1, 11))

edited Apr 05 '17 at 20:05

answered Apr 05 '17 at 20:04

It's `reversed` -- The list method is `.reverse` (just like `sorted` vs. `list.sort`) – mgilson Apr 05 '17 at 20:04
either is fine for my case I think :) – AsheKetchum Apr 05 '17 at 20:05
@mgilson true, thank you. I have corrected my misspelling – Giannis Spiliopoulos Apr 05 '17 at 20:05

3 Answers3