Create new list (or numpy.array) with a named list (or numpy.array)

Question

I have a name list, and I want to construct a new list of the same type of data inside the list. How can I do it? What if it is a numpy array?

x=[1,2,3,4]
newx=[x,5,6]
[[1, 2, 3, 4], 5, 6]

#numpy
y=np.array([0,1,2,3,4])
newy=[y,5,6]
[array([0, 1, 2, 3, 4]), 5, 6]

Desired output

[1, 2, 3, 4, 5, 6]

score 1 · Accepted Answer · answered Apr 05 '17 at 21:01

1

For mere Python lists you do:

x = [1, 2, 3, 4]
x += [5, 6]
>>> [1, 2, 3, 4, 5, 6]

and for numpy-arrays:

x = np.array([1, 2, 3, 4])
x = np.concatenate((x, np.array([5, 6])))
>>> np.array([1, 2, 3, 4, 5, 6])

Mind the double parentheses in np.concatenate, since the arguments must be passed as a tuple.

answered Apr 05 '17 at 21:01

rammelmueller

For the python list, what if I still want to keep the variable x and create a new x based on x? – MLE Apr 05 '17 at 21:03
1

you can use extend x = [1,2,3,4] y = [5,6] x.extend(y) – Alper Fırat Kaya Apr 05 '17 at 21:05

1 Answers1