String class split method

Question

I have written one java thread to split string

public void run() {

String input="Sasi|maran|rishabh";

String arr[]=input.split("|");
    for (int i = 0; i < arr.length; i++) {
        try{

            System.out.println(arr[i]);

            Thread.sleep(1000);

        }catch(Exception e){
            e.printStackTrace();
        }

    }

}

output expectation:

sasi
rishabh
maran

But what output i am getting :

S
a
s
i
|
m
a
r
a
n
|
r
i
s
h
a
b
h

I suggest you read the documentation for `String.split` *very carefully*, and consider what `|` means in regular expressions... — Jon Skeet, Apr 06 '17 at 10:02
Both answers below do not seem to deal explain how OP wants "rishabh" to print before "maran" when they are not reordering arr[] at all? — Sash Sinha, Apr 06 '17 at 10:04

score 0 · Answer 1 · answered Apr 06 '17 at 10:02

0

You need to escape the pipe | like: String[] arr = input.split("\\|"); and do System.out.print(element); instead of System.out.println(arr[i]);

answered Apr 06 '17 at 10:02

ΦXocę 웃 Пepeúpa ツ

47,427
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score 0 · Accepted Answer · answered Apr 06 '17 at 10:03

0

String#split method takes regex as an argument. | is a meta character, and it's have a special meaning in regex. Just escape it.

String arr[]=input.split("\\|");

answered Apr 06 '17 at 10:03

Suresh Atta

120,458
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score 0 · Answer 3 · answered Apr 06 '17 at 10:04

0

use the below code

 input.split("\\|")

answered Apr 06 '17 at 10:04

Zubair Nabi

1,016
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String class split method

3 Answers3