Swift 3 filter array of objects with elements of array

Question

array1 = array1.filter{ $0.arrayInsideOfArray1.contains(array2[0]) }

Code above works but I'm trying to check if all the elements of $0.arrayInsideOfArray1 match with all the elements of array2 not just [0]

Example:

struct User {
    var name: String!
    var age: Int!
    var hasPet: Bool!
    var pets: [String]!
}

var users: [User] = []

users.append(User(name: "testUset", age: 43, hasPet: true, pets: ["cat", "dog", "rabbit"]))
users.append(User(name: "testUset1", age: 36, hasPet: true, pets:["rabbit"]))
users.append(User(name: "testUset2", age: 65, hasPet: true, pets:["Guinea pigs", "Rats"]))

let petArr = ["cat", "dog", "rabbit"]

users = users.filter { $0.pets.contains(petArr[0]) }

What I want is any user that has any pet listed in the petArr!

You still haven't explained what results your expect to get with the code you posted. — rmaddy, Apr 07 '17 at 02:37
print(user) prints: (name: "testUset", age: 43, hasPet: true, pets: ["cat", "dog", "rabbit"])] But the result I wanted to get in this case would be: User(name: "testUset", age: 43, hasPet: true, pets: ["cat", "dog", "rabbit"])] User(name: "testUset1", age: 36, hasPet: true, pets:["rabbit"])] — NikaE, Apr 07 '17 at 02:42
So what you want is any user that has any pet listed in the `petArr`, correct? — rmaddy, Apr 07 '17 at 02:46
Then please update your question to make that clear. Update your question to show the results you want. — rmaddy, Apr 07 '17 at 02:49
@NikaE you should declare all properties of your structure as constantes and get rid of your IUO in all of them. structures don't require you to create its initializers. `struct User { let name: String let age: Int let hasPet: Bool let pets: [String] }` — Leo Dabus, Apr 07 '17 at 14:27

score 67 · Accepted Answer · answered Apr 07 '17 at 02:52

67

One approach is to update your filter to see if any value in pets is in the petArr array:

users = users.filter { $0.pets.contains(where: { petArr.contains($0) }) }

The first $0 is from the filter and it represents each User.

The second $0 is from the first contains and it represents each pet within the pets array of the current User.

answered Apr 07 '17 at 02:52

rmaddy

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The second `$0` is optional, writing `where: petArr.contains`is enough. – XLE_22 Dec 04 '21 at 09:25

score 4 · Answer 2 · edited Feb 07 '20 at 17:36

4

If elements inside the internal array are Equatable you can just write:

array1 = array1.filter{ $0.arrayInsideOfArray1 == array2 }

If they are not, you can make them, by adopting Equatable protocol and implementing:

func ==(lhs: YourType, rhs: YourType) -> Bool

edited Feb 07 '20 at 17:36

Iulian Onofrei

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answered Apr 07 '17 at 01:37

Zapko

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Swift 3 filter array of objects with elements of array

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