I need to get results like these:
2.1421 => 2.15
2.1401 => 2.15
2.14 => 2.14
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So you want to round up to the nearest `0.01`? – Willem Van Onsem Apr 07 '17 at 12:28
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1Use `round(num, 2)` – TrakJohnson Apr 07 '17 at 12:30
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yes, but to add 1 to 2nd decimal even if 3rd is 0 except if no 3rd digit – Feras Senjab Apr 07 '17 at 12:30
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the +0.005 trick doesn't work with 2.14... forget it. – Jean-François Fabre Apr 07 '17 at 12:31
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7Can't you just `math.ceil(num * 100) / 100.0`? – Jerrybibo Apr 07 '17 at 12:32
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1@Jean-FrançoisFabre it worked.. Thank u – Feras Senjab Apr 07 '17 at 12:32
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@FirasSy actually Jerrybibo comment is the best. – Jean-François Fabre Apr 07 '17 at 12:33
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oh yea for 2.14 not working – Feras Senjab Apr 07 '17 at 12:33
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yes this worked 100% Thank you very much @Jerrybibo – Feras Senjab Apr 07 '17 at 12:34
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2Beware of floats not doing what you might expect... Test your algorithms against 2.45 and 2.85. Note that `format(2.45, '.20f')` returns 2.45000000000000017764 and `format(2.85, '.20f')` returns 2.85000000000000008882 – PM 2Ring Apr 07 '17 at 12:48
1 Answers
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As @Jerrybibo mentioned, you'll need to use the ceil function, and to get the result to the nearest hundredths place, simply multiply your number by a hundred, run it through ceil and then divide that answer by 100. You can try it in IDLE.
>>> math.ceil(2.1421 * 100) / 100
2.15
Hope that helps.
ColorCodin
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I did not see that, actually...I had copied the answer from here and made it single line: http://stackoverflow.com/questions/8866046/python-round-up-integer-to-next-hundred – ColorCodin Apr 07 '17 at 12:43