Replace sed variable value from a json file

Question

I have a sed command that I use to insert a line into a shell script. The name of the script into which I insert varies in every env I'm trying to do this in. This works if I provide the values but when I need to repeat this across a large number of environments I need it to fetch these values from a json file. Any idea how I can achieve this?

Syntax -> sed -i '1 a if ! [ipaddress = <value> && OSTYPE = linux]; then exit(1); endif' qa-<envname>-vm1.sh

sed -i '1 a if ! [ipaddress = 0.0.0.0 && OSTYPE = linux]; then exit(1); endif' qa-QAF-vm1.sh

inserts

if ! [ipaddress = 0.0.0.0 && OSTYPE = linux]; then exit(1); endif after the first line in the file qa-QAF-vm1.sh.

Any ideas how I can fetch the ipaddress value and envname from a json file which lists these values?

Possible duplicate of [Unix command-line JSON parser?](http://stackoverflow.com/questions/3858671/unix-command-line-json-parser) — Kev, Apr 12 '17 at 08:51

score 0 · Answer 1 · answered Apr 12 '17 at 09:12

0

Use jq to query elements from a JSON data structure.

JSON='{"ipaddress": "10.10.10.10", "ostype": "linux"}'

ipaddress=$(jq -r .ipaddress <<<"$JSON")
ostype=$(jq -r .ostype <<<"$JSON")

echo $ipaddress
echo $ostype

answered Apr 12 '17 at 09:12

ceving

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Thanks @ceving - will give it a try. – Innocentspirit Apr 12 '17 at 09:26
I solved this issue myself by generating the aforementioned shell script using embedded Ruby without any seperate json parser – Innocentspirit Apr 13 '17 at 10:26

Replace sed variable value from a json file

1 Answers1