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Say I have below table. How do I pick up the latest previous value in case my joined table to not match the date and currency? On the null DKK value I want it to pick up 3. Note that dates do not exist every day since I do not load the tables on weekends.

Select
    PositionDate,
    Currency,
    T2.Value,
    isnull(t2.value, ? )
From t1
left join t2
on t1.currency = t2.Currency
and t1.PositionDate = t2.PositionDate

.

PositionDate    Currency        Value
2017-04-11      SEK               1
2017-04-11      DKK               NULL
2017-04-11      EUR               7
2017-04-10      SEK               4 
2017-04-10      DKK               3
2017-04-10      EUR               5
2017-04-07      SEK               4 
2017-04-07      DKK               3
2017-04-07      EUR               5

.

Haggan
  • 79
  • 8

2 Answers2

0

This will work for your case i think:

SELECT 
    t1.PositionDate,
    t1.Currency,
    COALESCE(t1.Value,t2.value) AS Value
FROM t1
LEFT join (SELECT MAX(PositionDate) AS PositionDate,Currency FROM t2 WHERE PositionDate < t1.PositionDate  GROUP BY Currency) tjoin
LEFT join t2 on tjoin.currency = t2.Currency and tjoin.PositionDate = t2.PositionDate
Succenna
  • 25
  • 2
0

You can Achieve it by using CTE and Case condition.

With cte as
(
    Select
        PositionDate,
        Currency,
        T2.Value,
    From t1
    left join t2
    on t1.currency = t2.Currency
    and t1.PositionDate = t2.PositionDate
        and t1.PositionDate = t2.PositionDate
)
select PositionDate, Currency, Value, 
   CASE WHEN ISNULL(value,'')='' THEN
    (Select top 1 from cte cin where cin.currency=cout.currency order by CONVERT(Date,PositionDate) desc)
   ELSE
    Value 
   END as Value2 
   From cte cout
ITSGuru
  • 194
  • 8